V Congreso Internacional de Gestión Financiera correccion costo v2

3) b h = 1/3 pi r 2 h
|−23|+|4|
BSOLUTE VALUE
1 r2 r3
(n 0)B0 + (n 1)B1 + (n 2)B2
pyramid = (1/3) b h
L=50,000
4 × π × r2
(4/3) pi r1 r2 r3
a+b =c
- 1/3 + 1/5 - 1/7 + ...
) b h = 1/3 pi r 2 h
r2 r3
|−23|+|4|
-(x+2) = 9
-x -2 = 9
-x = 11
x = -11
L=50,000
4 × π × r2
B = A (1 + r/n)NT - P
P = C (1 + r) t
Internacional
2/PI = sqrt2/2 * sqrt( 2 + sqrt2 )/2 * sqrt(2 + ( sqrt( 2 + sqrt2) ) )/2 * ...c
2. |a| ≥ 0
Gestión
PI/4 = 1/1 - 1/3 + 1/5 - 1/7 + ...
1. |–a| = |a|
cone = (1/3) b h = 1/3 pi r 2 h
(½) d1d2
P = C (1 + r) t
|−23|+|4|
ABSOLUTE VALUE
(n 0)B0 + (n 1)B1 + (n 2)B2
Financiera
pyramid = (1/3) b h
4 × π × r2
|a – b| ≥ |a| – |b
(½) d1d
Gamma(x)
= r x(integral)(0y
to Microcrédito
inf) e -rt t (x-1) dt
Educación
Financiera
V=5,000
Bucaramanga, Colombia
P = C (1 + r) t
2/PI = sqrt2/2 * sqrt( 2 + sqrt2 )/2 * sqrt(2 + ( sqrt( 2 + sqrt2) ) )/2 * ...c
28 y 29 de abril de 2016
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Hora: 2:00 p.m. a 7:00 p.m
Mayor.
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Red Académica en Finanzas
a+b =c
B = A (1 + r/n)NT - P
2. |a| ≥ 0
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Inscríbete en www.redafin.com.co y realiza el pago
en la cuenta de ahorros Bancolombia No. 79890075881
a nombre de FEDERACION SANTANDEREANA
DE ORGANISMOS NO GUBERNAMENTALES-FESANONG
y envía copia del comprobante de pago
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Apoyan
-(x
-x
-x
x=
Gamma(x+1) = x Gamma(x)
99 = XCIX
1. |–a| = |a|
2/PI = sqrt2/2 * sqrt( 2 + sqrt2 )/2 * sqrt(2 + ( sqrt( 2 + sqrt2) ) )/2 * ...c
gamma = - integral(0-inf) e^-x ln x
2. |a| ≥ 0
P = C e rt
Gamma(x) = r x(integral)(0 to inf) e -rt t (x-1) dt
Organiza
V Congreso
Gamma(x) = r x(integral)(0 to inf) e -rt t (x-1) dt
L=50,000
|a – b| ≥ |a| – |b
(½) d
B = A (1 + r/n)NT - P
(4/3) pi r1 r2 r3
a+b =c
Gamma(x+1) = x Gamma(x)
99 = XCIX
000
(n 0)B0 + (n 1)B1 + (n 2)B2
pyramid = (1/3) b h
t
a|
gamma = - integral(0-inf) e^-x ln x dx
2. |a| ≥ 0
SOLUTE VALUE
Gamma(x+1) = x Gamma(x)
|a – b| ≥ |a| – |b
1. |–a| = |a|
1. |–a| = |a|
a+b =c
¡Prepárate!
V=5,000
2/PI = sqrt2/2 * sqrt( 2 + sqrt2 )/2 * sqrt(2 + ( sqrt( 2 + sqrt2) ) )/2 * ...c
4 × π × r2
99 = XCIX
(½) d1d2
P = C (1 + r) t
|a|
pyramid = (1/3) b h
L=50,000
Gamma(x) = r x(integral)(0 to inf) e -rt t (x-1) dt
-(
-x
-x
x
(n 0)B0 + (n 1)B1 + (n 2)B2
P = C e rt
B = A (1 + r/n)NT - P
0
ABSOLUTE VALUE
|a – b| ≥ |a| – |b
rt
|−23|+|4|
2. |a| ≥ 0
Gamma(x+1) = x Gamma(x)
99 = XCIX
5,000
cone = (1/3) b h = 1/3 pi r 2 h
-(x+2) = 9
-x -2 = 9
-x = 11
x = -11
2. |a| ≥ 0