Calcula la potencia e intensidad de cortocircuito en los bornes del

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Calcula la potencia e intensidad de
cortocircuito en los bornes del primario y
del secundario del transformador 4.
Considera los siguientes valores para cada
elemento:
≔ 1000
⋅
URED ≔ 132
SccRED ≔ 1500
εccT1 ≔ 12%
Sn1 ≔ 20
εccT2a5 ≔ 4%
Sn2a5 ≔ 6
U2T1 ≔ 20
U2T2a5 ≔ 6
zL1 ≔ 0.07 ――
L1 ≔ 3
zL2a6 ≔ 0.12 ――
L2 ≔ 900
L3 ≔ 700
L4 ≔ 500
L5 ≔ 800
L6 ≔ 900
En primer lugar seleccionamos los valores base:
Sb ≔ 6
Ub1 ≔ URED = 132
Ub2 ≔ U2T1 = 20
A continuación calculamos las impedancias equivalentes de cada elemento:
URED 2
ZRED1 ≔ ―――
= 11.616
SccRED
URED 2
ZT1 ≔ εccT1 ⋅ ―――
= 104.544
Sn1
U2T1 2
ZT4 ≔ εccT2a5 ⋅ ―― = 2.667
Sn2a5
ZL1 ≔ zL1 ⋅ L1 = 0.21
ZL2 ≔ zL2a6 ⋅ L2 = 0.108
ZL3 ≔ zL2a6 ⋅ L3 = 0.084
ZL4 ≔ zL2a6 ⋅ L4 = 0.06
ZL5 ≔ zL2a6 ⋅ L5 = 0.096
ZL6 ≔ zL2a6 ⋅ L6 = 0.108
Hallamos los valores p.u. correspondientes:
Sb
= 0.004
Z'RED1 ≔ ZRED1 ⋅ ――
Ub1 2
Sb
Z'T1 ≔ ZT1 ⋅ ――
= 0.036
Ub1 2
Sb
Z'T4 ≔ ZT4 ⋅ ――
= 0.04
Ub2 2
Sb
Z'L1 ≔ ZL1 ⋅ ――
= 7.231 ⋅ 10 −5
2
Ub1
Sb
Z'L4 ≔ ZL4 ⋅ ――
= 9 ⋅ 10 −4
2
Ub2
Sb
Z'L2 ≔ ZL2 ⋅ ――
= 0.002
Ub2 2
Sb
Z'L5 ≔ ZL5 ⋅ ――
= 0.001
Ub2 2
Sb
Z'L3 ≔ ZL3 ⋅ ――
= 0.001
Ub2 2
Sb
Z'L6 ≔ ZL6 ⋅ ――
= 0.002
Ub2 2
Cortocircuito en el primario del T4
1
Z'eq ≔ Z'RED1 + Z'L1 + Z'T1 + ――――――――――
= 0.042
1
1
+ ――――――
――――
Sb
Z'L6 + Z'L5 Z'L2 + Z'L3 + Z'L4
= 143.667
Scc ≔ ――
Z'eq
Scc
= 4.147
Icc ≔ ――――
‾‾
3 ⋅ U2T1
Cortocircuito en el secundario del T4
1
Z'eq ≔ Z'RED1 + Z'L1 + Z'T1 + ――――――――――
+ Z'T4 = 0.082
1
1
+ ――――――
――――
Sb
Z'L6 + Z'L5 Z'L2 + Z'L3 + Z'L4
= 73.382
Scc ≔ ――
Z'eq
Scc
Icc ≔ ――――
= 2.118
‾‾
3 ⋅ U2T1
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