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-2 C= 8.016 kJ/m 2 -3 -4 J=J 0 -5 J =5.10 min -10 J =0 0 2 -8 0 2 R = 0.9575 R = 0.6360 -6 -4 -2 0 2 R = 0.9161 2 4 Ln(J-J ) 0 )LJXUD $MXVWH GH ODV IXQFLRQHV GH SUREDELOLGDG GHO 33FRQFHQVXUDGHGDWRVVHJ~QFULWHULRGHWDPDxRHF SDUDSUREHWDVFRQD\EPPGHHVSHVRU /DV )LJXUDV D \ E PXHVWUDQ OD HYROXFLyQ GH OD UHJUHVLyQ OLQHDO GH OD IXQFLyQ GH SUREDELOLGDG 246 Anales de Mecánica de la Fractura 28, Vol. 1 (2011) DFXPXODWLYDHFSDUDHO33FRQHVSHVRUHVGH\ PPUHVSHFWLYDPHQWHWRPDQGRGLIHUHQWHVYDORUHVGH- \WHQLHQGRHQFXHQWDHOFULWHULRGHWDPDxRGHILQLGRSRU ODHFXDFLyQ/RVYDORUHVGH-GHO33GHODVSUREHWDV FRQ \ PP GH HVSHVRU WUDV WHQHU HQ FXHQWD OD H[FOXVLyQGHGDWRVVHJ~QHOFULWHULRGHWDPDxRVRQ \N-PUHVSHFWLYDPHQWH/DVGLIHUHQFLDVHQ-FRQ HO HVSHVRU IXHURQ GHO \ HO KHFKR GH XQ DOFDQ]DU XQLIRUPLGDGHQHOYDORUSXHGHVHUGHELGRDTXHHOYDORU GH-OLPHFHVWiGHVDUUROODGRSDUDPHWDOHV>@\PX\ SUREDEOHPHQWHGHEHQVHUUHGHILQLGRVSDUDSROtPHURV /DV)LJXUDVD\EPXHVWUDQODVVXSHUILFLHVGHIUDFWXUD FDUDFWHUtVWLFDV SDUD ODV SUREHWDV GH \ PP GH 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250 200 2 (a) EPR B= 6.35 mm N= 58 150 0 Ln(Ln(1/(1-P ))) 100 -1 i Fuerza (N) 1 EPR 50 B= 6.35 mm m= 2.508 -2 C= 20.60 kJ/m 2 -3 B= 9 mm -4 0 0 0,5 1 1,5 2 2,5 3 3,5 4 Desplazamiento (mm) -5 )LJXUD&XUYDVIXHU]DGHVSOD]DPLHQWRFDUDFWHUtVWLFDV GHSUREHWDVGH(35FRQ\PPGHHVSHVRU J =J 0 J =8.5 min 0 2 -6 -8 J =0 0 2 2 R = 0.9638 R = 0.9303 R = 0.6076 -6 -4 -2 0 2 4 Ln(J-J ) D 0 2 (b) EPR B= 9 mm N= 56 1 -1 i Ln(Ln(1/(1-P ))) 0 PP E m= 1.951 -2 C= 12.509 kJ/m 2 -3 -4 -5 J =J 0 J =8.58 min -6 -10 J =0 0 2 -8 0 2 2 R = 0.9877 R = 0.9118 R = 0.6626 -6 -4 -2 0 2 4 Ln(J-J ) 0 PP )LJXUD $MXVWH GH ODV IXQFLRQHV GH SUREDELOLGDG GHO (35SDUDSUREHWDVFRQD\EPPGHHVSHVRU )LJXUD6XSHUILFLHVGHIUDFWXUDWtSLFDVGHSUREHWDVGHO (35FRQHVSHVRUHVGHD\EPP 247 Anales de Mecánica de la Fractura 28, Vol. 1 (2011) (IHFWRGHOFRQWHQLGRGHHWLOHQR SURFHVVLQJ DQG DSSOLFDWLRQV HGLWDGR SRU +DQVHU 3XEOLVKHUV0XQLFK /DWDEODUHFRSLODORVYDORUHVGHWHQDFLGDGGHIUDFWXUD XPEUDO GHO 33 \ (35 PHGLGRV HQ SUREHWDV FRQ 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