Temel Formuller sin2x+cos2x=1 cos(x+y)=cosx cosy - sinx siny sin(x+y)=sinx cosy + siny cosx sin(-x)=- sinx cos(-x)=cos(x) tan(-x)=-tan(x) cos(x-y)=cosx cos y + sinx sin y sin(x-y)=sinx cosy - siny cos x 1 [cos(x+y) +cos(x-y)] 2 1 sinx siny = [ cos(x-y)- cos(x+y)] 2 1 sinx cosy = [ sin(x+y)+ sin(x-y)] 2 cosx cosy= cos(x+90)=– sinx cos(x- 90)= sinx sin(x+ 90)= cosx sin(x- 90)= -cosx cos(90-q)= sinq sin(90-q)= cosq cos(2x) = 2cos2x -1 1 2 cos2x = [ 1+cos(2x)] cos(2x) =1- 2sin2x 1 2 tan x = sin x = cos x = q -1 2 q cos q = 1-2sin2 2 q q sinq =2 sin cos 2 2 1 3 3 sin q= = - sin(3q) + sin q 4 4 cos q = 2cos2 sin(3q)= -4sin3q +3sinq cos3q= = 1 3 cos3q + cosq 4 4 cos3q=4 cos3q -3 cosq tan x + tan y 1 − tan x tan y tan x − tan y tan( x − y ) = 1 + tan x tan y 2 tan x tan(2 x) = 1 − tan 2 x q 2 tan 2 tan(q) = 2 q 1 − tan 2 tan( x + y ) = 1 − sin 2 x tan x 1 − cos2 x cos x = 1 + tan 2 x 1 1 + tan 2 x x 1 − tan 2 cos x = 2 x 1 + tan 2 x 2 tan 2 sin x = 2 x 1 + tan 2 ------------------ ---Basit hatirlama teknigi 1 + x2 x q 1 x tan q = =x 1 sin q = x 1+ x sin2x = [ 1-cos(2x)] sin2x =2 sinx cosx sin x cos q = = 2 1 1+ x = 2 tan q 1 + tan 2 q 1 1 + tan 2 q sin 2q=2sin q cos q= 2q=p q=p/2 sin p = 2 tan p 2 1 + tan 2 p 2 2x = 2 tan q2 2 1 + x 1 + tan q