DALCAME www.dalcame.com __________________________________________________________ DISEÑO DE FILTROS A –60 dB/dec FILTRO PASABANDA CON Fl=0.1Hz y Fh=100Hz Procedimiento de diseño: a. Escoja el Amplificador Operacional: LF356 con RRMC=100db, entrada=1012Ω b. B=100Hz-0.1Hz=99.9Hz c. Fr = (100 Hz )(0.1Hz ) = 3.1622 Hz (99.9 Hz ) 2 99.9 Hz d. Fl = + (3.1622 Hz ) 2 − = 0.0999 Hz 4 2 3.1622 Hz = 0.0316 = Banda Ancha e. Q = 99.9 Hz Banda Ancha Pasabajas Fh=100Hz a. C3 = 0.1µ F b. f c = 100 Hz R = 15.915k Ω 0.1µ F C1 = = 50000 pF = 0.05µ F d. 2 C2 = 2(0.1µ F ) = 200000 pF = 0.2 µ F c. e. f. R1 = R2 = R3 = 15.915k Ω RF 1 = 2(15.915k Ω) = 31.83k Ω RF 2 = 15.915k Ω Pasaaltas fl=0.1Hz a. C3 = 10 µ F b. c. d. e. f. f c = 0.1Hz 1 R3 = = 159.154k Ω 2π f c C 159.154k Ω R2 = = 79.57 k Ω 2 R1 = 318.308k Ω RF 1 = 318.308k Ω RF 2 = 159.154k Ω Impedancia DALCAME www.dalcame.com __________________________________________________________ FILTRO PASABAJAS CON fc=100Hz a. Amplificador Operacional: LF356 b. C3 = 0.1µ F c. d. e. f. C3 = 50000 pF = 0.05µ F 2 C2 = 2C3 = 200000 pF = 0.2 µ F 1 R= = 15.915k Ω 2π f c C3 R1 = R2 = R3 = R = 15.915k Ω RF 1 = 2(15.915k Ω) = 31.83k Ω RF 2 = 15.915k Ω C1 = FILTRO PASAALTAS CON fc=0.1Hz a. Amplificador Operacional: LF356 b. C = 10 µ F DALCAME www.dalcame.com __________________________________________________________ 1 = 159.1549k Ω 2π f c C d. R1 = 2(159.1549k Ω) = 318.3098k Ω 159.1549k Ω e. R2 = = 79.5774k Ω 2 RF 1 = 318.3098k Ω c. f. R3 = RF 2 = 159.1549k Ω FILTRO RECHAZA BANDA CON fr=120Hz y B=6Hz a. Amplificador Operacional: LF356 b. c. d. fl = 36 6 B2 B + fr 2 − = + 1202 − = 117.04 Hz 4 2 4 2 B = fH − fL f H = B + f L = 123.04 Hz C = 1µ F f r = (123.04 Hz )(117.04 Hz ) = 120 Hz 120 f. Q = = 20 6 0.1591 0.1591 = = 26.517k Ω g. R = BC (6)(1µ F ) R 26.517k Ω = = 33.19Ω h. Rr = 2 2Q − 1 2(20) 2 − 1 e. DALCAME www.dalcame.com __________________________________________________________