REGLAS DE DERIVACIÓN u = u ( x) , v = v ( x) y w = w( x) (u, v y w son funciones de x) k, a y n son constantes k′ = 0 x′ = 1 ( u + v )′ = u′ + v′ ( u − v )′ = u′ − v′ ( u ⋅ v )′ = u′ ⋅ v + u ⋅ v′ ⎛ u ⎞′ u ′ ⋅ v − u ⋅ v′ ⎜ ⎟ = v2 ⎝v⎠ ( k ⋅ u )′ = k ⋅ u′ ⎛ u ⎞′ u ′ ⎜ ⎟ = ⎝k⎠ k ( u ⋅ v ⋅ w )′ = u′ ⋅ v ⋅ w + u ⋅ v′ ⋅ w + u ⋅ v ⋅ w′ ( x )′ = n ⋅ x n ( x )′ = n x n n x x x n ( a )′ = a u u n −1 ⋅ ln a ⋅ u ′ ( e )′ = e x u u ⋅u ′ u′ ⋅ log a e u u′ ( ln u )′ = u ( log a x )′ = ( log a u )′ = 1 ⋅ log a e x 1 ( ln x )′ = x (u )′ = v ⋅ u v ( tg x )′ = ⋅ u′ n n −1 ⋅ ln a ( e )′ = e n −1 ( u )′ = n ⋅ uu′ 1 n ( a )′ = a (u )′ = n ⋅ u n −1 v −1 ⋅ u ′ + u v ⋅ ln u ⋅ v′ ( sen x )′ = cos x ( sen u )′ = u′ ⋅ cos u ( cos x )′ = − sen x ( cos u )′ = −u′ ⋅ sen u ( tg u )′ = 1 = sec 2 x = 1 + tg 2 x 2 cos x u′ = u′ ⋅ sec2 u = u′ ⋅ 1 + tg 2 u 2 cos u ( ( cosec x )′ = − cosec x ⋅ cotg x ( cosec u )′ = −u′ ⋅ cosec u ⋅ cotg u ( sec x )′ = sec x ⋅ tg x ( sec u )′ = u′ ⋅ sec u ⋅ tg u ( cotg x )′ = − ( 1 = − cosec 2 x = − 1 + cotg 2 x 2 sen x 1 ( arcsen x )′ = 1 − x2 ( arccos x )′ = ( arctg x )′ = −1 1 − x2 1 1 + x2 ) ( cotg u )′ = ) −u ′ = −u′ ⋅ cosec 2 u = −u′ ⋅ 1 + cotg 2 u 2 sen x u′ ( arcsen u )′ = 1− u2 ( ( arccos u )′ = ( arctg u )′ = I.E.S. “Miguel de Cervantes” (Granada) – Departamento de Matemáticas – GBG −u′ 1− u2 u′ 1+ u2 )